The angular speed of a flywheel moving with u | vedclass

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(A) The formula for angular velocity under uniform angular acceleration is $\omega = \omega_{0} + \alpha t$.Here, the initial angular speed $\omega_{0

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(A) The formula for angular velocity under uniform angular acceleration is $\omega = \omega_{0} + \alpha t$.Here, the initial angular speed $\omega_{0} = 1200\,rpm$ and the final angular speed $\omega = 3120\,rpm$.The time interval is $t = 16\,s$.First, convert the angular speeds from $rpm$ to $rad/s$ using the relation $1\,rpm = \frac{2\pi}{60}\,rad/s$.The change in angular speed is $\Delta\omega = 3120 - 1200 = 1920\,rpm$.Converting this to $rad/s$: $\Delta\omega = 1920 	imes \frac{2\pi}{60} = 32 	imes 2\pi = 64\pi\,rad/s$.The angular acceleration $\alpha$ is given by $\alpha = \frac{\Delta\omega}{t} = \frac{64\pi}{16} = 4\pi\,rad/s^{2}$.

The angular speed of a flywheel moving with uniform angular acceleration changes from $1200\,rpm$ to $3120\,rpm$ in $16\,s$. The angular acceleration in $rad/s^{2}$ is: (in $\pi$)

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