The angular speed of the minute hand of a clock in degrees per second is

What is the direction of velocity at any point on the circle for a particle undergoing uniform circular motion?

$A$ particle is moving along a circular path with a constant speed of $10\,m/s.$ What is the magnitude of the change in velocity of the particle,when it moves through an angle of $60^{\circ}$ around the centre of the circle? .......... $m/s$

If the angular velocity of a merry-go-round is $60^o/s$ and you are $3.5\,m$ from the centre of rotation,your linear velocity will be

The angular velocity of the seconds hand of a watch will be:

$A$ body moves along a circular path of diameter $30 \text{ cm}$. It starts from one end of a diameter, moves along the circular path, and reaches the other end of the diameter in $3 \text{ seconds}$. The angular speed of the body in radians per second is: