The antenna current of an AM transmitter is 8 | vedclass

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(D) The relationship between the total antenna current $(I_t)$ and the carrier current $(I_c)$ in an $AM$ transmitter is given by the formula: ${\left

Vedclass · Accepted Answer

$71$

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(D) The relationship between the total antenna current $(I_t)$ and the carrier current $(I_c)$ in an $AM$ transmitter is given by the formula: ${\left( {\frac{{{I_t}}}{{{I_c}}}} ight)^2} = 1 + \frac{{{m^2}}}{2}$ where $m$ is the modulation index.Given: $I_c = 8 	ext{ A}$ and $I_t = 8.96 	ext{ A}$.Substituting the values: ${\left( {\frac{{8.96}}{8}} ight)^2} = 1 + \frac{{{m^2}}}{2}$ $(1.12)^2 = 1 + \frac{{{m^2}}}{2}$ $1.2544 = 1 + \frac{{{m^2}}}{2}$ $0.2544 = \frac{{{m^2}}}{2}$ $m^2 = 0.5088$ $m = \sqrt{0.5088} \approx 0.713$ Thus,the percentage modulation is $m 	imes 100 \approx 71\%$.

The antenna current of an $AM$ transmitter is $8 \text{ A}$ when only the carrier is sent,but it increases to $8.96 \text{ A}$ when the carrier is sinusoidally modulated. The percentage modulation is.......$\%$

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