The approximate value of sqrt[3]{0.026} is | vedclass

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(B) Let $f(x) = x^{\frac{1}{3}}$.Then,$f'(x) = \frac{1}{3} x^{-\frac{2}{3}} = \frac{1}{3x^{\frac{2}{3}}}$.We choose $a = 0.027$ because $\sqrt[3]{0.02

Vedclass · Accepted Answer

$0.2963$

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(B) Let $f(x) = x^{\frac{1}{3}}$.Then,$f'(x) = \frac{1}{3} x^{-\frac{2}{3}} = \frac{1}{3x^{\frac{2}{3}}}$.We choose $a = 0.027$ because $\sqrt[3]{0.027} = 0.3$,and $h = -0.001$ such that $a + h = 0.026$.Using the linear approximation formula $f(a + h) \approx f(a) + hf'(a)$:$f(a) = (0.027)^{\frac{1}{3}} = 0.3$.$f'(a) = \frac{1}{3(0.027)^{\frac{2}{3}}} = \frac{1}{3(0.09)} = \frac{1}{0.27}$.Substituting these values:$f(0.026) \approx 0.3 + (-0.001) 	imes \frac{1}{0.27}$.$f(0.026) \approx 0.3 - \frac{0.001}{0.27} \approx 0.3 - 0.0037 = 0.2963$.

The approximate value of $\sqrt[3]{0.026}$ is

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