The area of a rectangle is 460 , m^2. If the | vedclass

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(D) Let the breadth of the rectangle be $b \, m$.Since the length is $15 \%$ more than the breadth,the length $l = b + 0.15b = 1.15b \, m$.The area of

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$20$

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(D) Let the breadth of the rectangle be $b \, m$.Since the length is $15 \%$ more than the breadth,the length $l = b + 0.15b = 1.15b \, m$.The area of a rectangle is given by the formula: $	ext{Area} = l 	imes b$.Substituting the given values: $1.15b 	imes b = 460$.$1.15b^2 = 460$.$b^2 = \frac{460}{1.15} = 400$.Taking the square root of both sides: $b = \sqrt{400} = 20 \, m$.Therefore,the breadth of the rectangular field is $20 \, m$.

The area of a rectangle is $460 \, m^2$. If the length is $15 \%$ more than the breadth,what is the breadth of the rectangular field? (in $metres$)

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