The area of a rectangular field (in m^{2}) of | vedclass

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(C) The area of a rectangle is given by the formula: $Area = 	ext{Length} 	imes 	ext{Breadth}$.Given,Length $= 55.3 \ m$ (which has $3$ significant

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$14 	imes 10^{2}$

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(C) The area of a rectangle is given by the formula: $Area = 	ext{Length} 	imes 	ext{Breadth}$.Given,Length $= 55.3 \ m$ (which has $3$ significant figures) and Breadth $= 25 \ m$ (which has $2$ significant figures).Calculating the product: $55.3 	imes 25 = 1382.5 \ m^{2}$.According to the rules of significant figures,the result of multiplication should have the same number of significant figures as the measurement with the least number of significant figures.Here,the least number of significant figures is $2$ (from $25 \ m$).Rounding $1382.5$ to $2$ significant figures,we get $1400 \ m^{2}$,which can be written as $14 	imes 10^{2} \ m^{2}$.

The area of a rectangular field (in $m^{2}$) of length $55.3 \ m$ and breadth $25 \ m$ after rounding off the value for correct significant digits is

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