The area of a triangle with vertices $A (3,0), B (7,0)$ and $C (8,4)$ is

The fourth vertex $D$ of a parallelogram $ABCD$ whose three vertices are $A(-2,3)$,$B(6,7)$,and $C(8,3)$ is

$P(x_{1}, y_{1})$ and $Q(x_{2}, y_{2})$ are the given points. If $\overline{PQ}$ is parallel to the $X$-axis,then...........

Prove that the point $P(7, 5)$ is equidistant from the points $A(2, 4)$ and $B(6, 10)$.

If $P(1, 12)$ divides the line segment $\overline{AB}$ starting from $A$ in the ratio $2:1$ and $A(3, 8)$,then the coordinates of $B$ are $\ldots \ldots$

State whether the following statement is true or false. Justify your answer.
Point $P(0, 2)$ is the point of intersection of the $y$-axis and the perpendicular bisector of the line segment joining the points $A(-1, 1)$ and $B(3, 3)$.