(B) Let the length of each equal side be $x \, m$.The sides of the triangle are $x, x,$ and $64$.The semi-perimeter $s = \frac{x + x + 64}{2} = x + 32

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(B) Let the length of each equal side be $x \, m$.The sides of the triangle are $x, x,$ and $64$.The semi-perimeter $s = \frac{x + x + 64}{2} = x + 32$.Using Heron's formula,Area $= \sqrt{s(s-a)(s-b)(s-c)}$.$1600 = \sqrt{(x+32)(x+32-x)(x+32-x)(x+32-64)}$.$1600 = \sqrt{(x+32)(32)(32)(x-32)}$.$1600 = 32 \sqrt{(x+32)(x-32)}$.$50 = \sqrt{x^{2} - 32^{2}}$.Squaring both sides,$2500 = x^{2} - 1024$.$x^{2} = 3524$.$x = \sqrt{3524} \approx 59.36 \, m$.

Competitive Quantitative Aptitude Mensuration Measurement of Area

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The area of a triangular lawn is $1600 \, m^{2}$. If one side is $64 \, m$ long and the other two sides are equal in length,the length of each equal side is......$m$

A
$60.37$
B
$59.36$
C
$60.36$
D
None of these

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Measurement of Area

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The area of a triangular lawn is $1600 \, m^{2}$. If one side is $64 \, m$ long and the other two sides are equal in length,the length of each equal side is......$m$

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One of the diagonals of a rhombus is double the other diagonal. Its area is $25\, cm^{2}$. The sum of the diagonals is.......$cm$

The side of a square exceeds the side of another square by $4\, cm$ and the sum of the areas of the two squares is $400\, cm^2$. The dimensions of the squares are?

If the length of a rectangle is increased in the ratio $6:7$ and its breadth is diminished in the ratio $5:4$,then its area will be changed in the ratio:

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The tangents drawn at points $A$ and $B$ of a circle with centre $O$ meet at $P$. If $\angle AOB = 120^{\circ}$ and $AP = 6 \text{ cm}$,then what is the area of triangle $APB$ (in $\text{cm}^{2}$)?

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