The areas of two square fields are 420.25 ; m | vedclass

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(C) Let the sides of the two square fields be $s_1$ and $s_2$ respectively.Given that the area of the first square is $A_1 = 420.25 \; m^2$ and the ar

Vedclass · Accepted Answer

$41:42$

Vedclass · Answer

(C) Let the sides of the two square fields be $s_1$ and $s_2$ respectively.Given that the area of the first square is $A_1 = 420.25 \; m^2$ and the area of the second square is $A_2 = 441 \; m^2$.The side of a square is given by the formula $s = \sqrt{A}$.Therefore,$s_1 = \sqrt{420.25} = 20.5 \; m$ and $s_2 = \sqrt{441} = 21 \; m$.The ratio of their sides is $s_1 : s_2 = 20.5 : 21$.To simplify the ratio,multiply both terms by $2$: $(20.5 	imes 2) : (21 	imes 2) = 41 : 42$.

The areas of two square fields are $420.25 \; m^2$ and $441 \; m^2,$ respectively. The ratio of their sides is

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