The armature of a DC motor has 20,Omega resis | vedclass

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(D) For a $DC$ motor,the current $I$ is given by the formula:$I = \frac{V - E}{R}$where $V$ is the supply voltage,$E$ is the back $EMF$,and $R$ is the

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$190$

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(D) For a $DC$ motor,the current $I$ is given by the formula:$I = \frac{V - E}{R}$where $V$ is the supply voltage,$E$ is the back $EMF$,and $R$ is the armature resistance.Given:$V = 220\,V$$I = 1.5\,A$$R = 20\,\Omega$Substituting the values into the equation:$1.5 = \frac{220 - E}{20}$$1.5 	imes 20 = 220 - E$$30 = 220 - E$$E = 220 - 30$$E = 190\,V$Therefore,the back $EMF$ is $190\,V$.

The armature of a $DC$ motor has $20\,\Omega$ resistance. It draws a current of $1.5\,A$ when run by a $220\,V$ $DC$ supply. The value of the back $EMF$ induced in it will be......$V$

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