The atomic number of an element is 17. The nu | vedclass

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(C) The electronic configuration of an element with atomic number $17$ $(Cl)$ is: $1s^2 2s^2 2p^6 3s^2 3p^5$.Its valence shell is the $n=3$ shell,whic

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$3$

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(C) The electronic configuration of an element with atomic number $17$ $(Cl)$ is: $1s^2 2s^2 2p^6 3s^2 3p^5$.Its valence shell is the $n=3$ shell,which has the configuration $3s^2 3p^5$.Representing the orbitals:$3s^2$: One orbital containing a pair of electrons.$3p^5$: Three orbitals,where two orbitals contain electron pairs and one orbital contains a single electron.Total number of orbitals containing electron pairs in the valence shell $= 1 (	ext{from } 3s) + 2 (	ext{from } 3p) = 3$.

The atomic number of an element is $17$. The number of orbitals containing electron pairs in its valence shell is

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