The autorickshaw fare in a city is charged $Rs. 10$ for the first kilometer and $Rs. 4$ per kilometer for the subsequent distance covered. Write the linear equation to express the above statement and draw the graph of the linear equation.

(N/A) Let the total distance covered be $x \text{ km}$ and the total fare charged be $Rs. y$.
For the first $1 \text{ km}$,the fare is $Rs. 10$.
For the remaining distance $(x - 1) \text{ km}$,the fare is $Rs. 4(x - 1)$.
Therefore,the total fare $y$ is given by:
$y = 10 + 4(x - 1)$
$y = 10 + 4x - 4$
$y = 4x + 6$
Thus,the required linear equation is $4x - y + 6 = 0$.
To draw the graph,we find two points on the line:
If $x = 0$,then $y = 4(0) + 6 = 6$. Point: $(0, 6)$.
If $x = -1$,then $y = 4(-1) + 6 = 2$. Point: $(-1, 2)$.
Plotting these points on a Cartesian plane and joining them gives the required straight line graph.