(A) The average kinetic energy $(K.E.)$ of an ideal gas per mole is given by the formula: $K.E. = \frac{3}{2} RT$. Given that the gas constant $R \app

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Three times the absolute temperature

(A) The average kinetic energy $(K.E.)$ of an ideal gas per mole is given by the formula: $K.E. = \frac{3}{2} RT$. Given that the gas constant $R \approx 2 \ \text{cal} \ K^{-1} \ mol^{-1}$. Substituting the value of $R$: $K.E. = \frac{3}{2} \times 2 \times T = 3T$. Therefore,the average $K.E.$ is approximately $3$ times the absolute temperature $(T)$.

Class 11 Chemistry States of Matter Kinetic molecular theory of gases and Molecular collisions

Medium

The average $K.E.$ of an ideal gas in calories per mole is approximately equal to

A
Three times the absolute temperature
B
Absolute temperature
C
Two times the absolute temperature
D
$1.5$ times the absolute temperature

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The average $K.E.$ of an ideal gas in calories per mole is approximately equal to

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