The average e.m.f. induced in a coil in which | vedclass

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(B) The formula for the induced $e.m.f.$ $(e)$ in a coil due to self-inductance $(L)$ is given by $e = -L \frac{di}{dt}$.Taking the magnitude,we have

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$0.2$

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(B) The formula for the induced $e.m.f.$ $(e)$ in a coil due to self-inductance $(L)$ is given by $e = -L \frac{di}{dt}$.Taking the magnitude,we have $|e| = L \frac{|di|}{dt}$.Given:Change in current,$di = 4 \ A - 2 \ A = 2 \ A$.Time interval,$dt = 0.05 \ s$.Induced $e.m.f.$,$|e| = 8 \ V$.Substituting these values into the formula:$8 = L 	imes \frac{2}{0.05}$$8 = L 	imes 40$$L = \frac{8}{40} = 0.2 \ H$.Therefore,the self-inductance of the coil is $0.2 \ H$.

The average $e.m.f.$ induced in a coil in which the current changes from $2 \ A$ to $4 \ A$ in $0.05 \ s$ is $8 \ V.$ What is the self-inductance of the coil in $H$?

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