The average kinetic energy of H_2 molecules a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The average kinetic energy $(K_{avg})$ of a gas molecule is given by the formula: $K_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann const

Vedclass · Accepted Answer

$E$

Vedclass · Answer

(A) The average kinetic energy $(K_{avg})$ of a gas molecule is given by the formula: $K_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.From this formula,it is clear that the average kinetic energy depends only on the absolute temperature $T$ and is independent of the mass or nature of the gas molecule.Given that the average kinetic energy of $H_2$ molecules at $300 \ K$ is $E$,and since the temperature for $O_2$ molecules is also $300 \ K$,the average kinetic energy of $O_2$ molecules will also be $E$.

The average kinetic energy of $H_2$ molecules at $300 \ K$ is $E$. At the same temperature,the average kinetic energy of an $O_2$ molecule is:

Similar Questions

The translatory kinetic energy of a gas per $gm$ is

Kinetic energy per unit volume is $E$. The pressure exerted by the gas is given by

The average kinetic energy of a helium atom at $30^oC$ is

In a vessel,the gas is at pressure $P_0$. If the mass of all the molecules is halved and their speed is doubled,then the resultant pressure will be

At $27^{\circ}C$ temperature,the kinetic energy of an ideal gas is $E_1$. If the temperature is increased to $327^{\circ}C$,then the kinetic energy would be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module