The average number of photons emitted per sec | vedclass

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(A) The power $P$ of the laser is the total energy emitted per second. The energy of a single photon is given by $E = \frac{hc}{\lambda}$.Therefore,th

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$2 	imes 10^{16}$

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(A) The power $P$ of the laser is the total energy emitted per second. The energy of a single photon is given by $E = \frac{hc}{\lambda}$.Therefore,the number of photons emitted per second $n$ is given by $n = \frac{P}{E} = \frac{P \lambda}{hc}$.Given values: $P = 6.6 	imes 10^{-3} \,W$,$\lambda = 600 	imes 10^{-9} \,m$,$h = 6.6 	imes 10^{-34} \,J \cdot s$,and $c = 3 	imes 10^8 \,m/s$.Substituting these values into the formula:$n = \frac{(6.6 	imes 10^{-3} \,W) 	imes (600 	imes 10^{-9} \,m)}{(6.6 	imes 10^{-34} \,J \cdot s) 	imes (3 	imes 10^8 \,m/s)}$$n = \frac{6.6 	imes 600 	imes 10^{-12}}{6.6 	imes 3 	imes 10^{-26}}$$n = \frac{600 	imes 10^{-12}}{3 	imes 10^{-26}}$$n = 200 	imes 10^{14} = 2 	imes 10^{16}$ photons per second.

The average number of photons emitted per second by a laser of power $6.6 \times 10^{-3} \,W$ producing light of wavelength $600 \,nm$ is (Planck's constant,$h = 6.6 \times 10^{-34} \,J \cdot s$):

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