The average of three consecutive odd numbers | vedclass

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Question

(B) Let the three consecutive odd numbers be $x$,$x+2$,and $x+4$.The average of these numbers is $\frac{x + (x+2) + (x+4)}{3} = \frac{3x+6}{3} = x+2$.

Vedclass · Accepted Answer

$77$

Vedclass · Answer

(B) Let the three consecutive odd numbers be $x$,$x+2$,and $x+4$.The average of these numbers is $\frac{x + (x+2) + (x+4)}{3} = \frac{3x+6}{3} = x+2$.According to the problem,the average is $52$ more than $\frac{1}{3}$ of the largest number $(x+4)$:$x+2 = \frac{1}{3}(x+4) + 52$Multiply the entire equation by $3$ to clear the fraction:$3(x+2) = (x+4) + 52 	imes 3$$3x + 6 = x + 4 + 156$$3x + 6 = x + 160$$2x = 154$$x = 77$Thus,the smallest number is $77$.

The average of three consecutive odd numbers is $52$ more than $\frac{1}{3}$ of the largest of these numbers. What is the smallest of these numbers?

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