The average speed of a car is 1 frac{4}{5} ti | vedclass

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(C) Step $1$: Calculate the speed of the tractor.Speed of the tractor $= \frac{	ext{Distance}}{	ext{Time}} = \frac{575 \, km}{23 \, hours} = 25 \, k

Vedclass · Accepted Answer

$360$

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(C) Step $1$: Calculate the speed of the tractor.Speed of the tractor $= \frac{	ext{Distance}}{	ext{Time}} = \frac{575 \, km}{23 \, hours} = 25 \, km/h$.Step $2$: Calculate the speed of the bus.Given that the speed of the bus is twice the speed of the tractor.Speed of the bus $= 2 	imes 25 \, km/h = 50 \, km/h$.Step $3$: Calculate the speed of the car.The average speed of the car is $1 \frac{4}{5} = \frac{9}{5}$ times the speed of the bus.Speed of the car $= \frac{9}{5} 	imes 50 \, km/h = 90 \, km/h$.Step $4$: Calculate the distance covered by the car in $4 \, hours$.Distance $= 	ext{Speed} 	imes 	ext{Time} = 90 \, km/h 	imes 4 \, hours = 360 \, km$.

The average speed of a car is $1 \frac{4}{5}$ times the average speed of a bus. $A$ tractor covers $575 \, km$ in $23 \, hours$. How much distance will the car cover in $4 \, hours$ if the speed of the bus is twice the speed of the tractor? (in $km$)

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