The base current in a transistor circuit chan | vedclass

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(C) The current gain $\beta$ of a transistor is defined as the ratio of the change in collector current to the change in base current: $\beta = \frac{

Vedclass · Accepted Answer

$40$

Vedclass · Answer

(C) The current gain $\beta$ of a transistor is defined as the ratio of the change in collector current to the change in base current: $\beta = \frac{\Delta I_C}{\Delta I_B}$.Given:Change in base current $\Delta I_B = 140 \mu A - 45 \mu A = 95 \mu A = 95 	imes 10^{-6} 	ext{ A}$.Change in collector current $\Delta I_C = 4.0 	ext{ mA} - 0.2 	ext{ mA} = 3.8 	ext{ mA} = 3.8 	imes 10^{-3} 	ext{ A}$.Substituting these values into the formula:$\beta = \frac{3.8 	imes 10^{-3}}{95 	imes 10^{-6}} = \frac{3800 	imes 10^{-6}}{95 	imes 10^{-6}} = 40$.Therefore,the current gain is $40$.

The base current in a transistor circuit changes from $45 \mu A$ to $140 \mu A$. Accordingly,the collector current changes from $0.2 \text{ mA}$ to $4.0 \text{ mA}$. The current gain is

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