The base of a prism is a right-angled triangl | vedclass

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Question

(A) The base is a right-angled triangle with sides $a = 5 \, cm$ and $b = 12 \, cm$.The hypotenuse $c = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{16

Vedclass · Accepted Answer

$360$

Vedclass · Answer

(A) The base is a right-angled triangle with sides $a = 5 \, cm$ and $b = 12 \, cm$.The hypotenuse $c = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \, cm$.The perimeter of the base $P = 5 + 12 + 13 = 30 \, cm$.The lateral surface area of the prism $= P 	imes 	ext{height} = 30 	imes 10 = 300 \, cm^2$.The area of the triangular base $A_{base} = \frac{1}{2} 	imes 5 	imes 12 = 30 \, cm^2$.The total surface area of the prism $= 	ext{Lateral surface area} + 2 	imes A_{base} = 300 + 2(30) = 300 + 60 = 360 \, cm^2$.

The base of a prism is a right-angled triangle with $2$ sides $5 \, cm$ and $12 \, cm$. The height of the prism is $10 \, cm$. The total surface area of the prism is......$cm^2$

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