The base of a right triangle is 8 , cm and it | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the right triangle be $	riangle ABC$ where $\angle B = 90^{\circ}$.Given: Base $BC = 8 \, cm$ and hypotenuse $AC = 10 \, cm$.According to the

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(A) Let the right triangle be $	riangle ABC$ where $\angle B = 90^{\circ}$.Given: Base $BC = 8 \, cm$ and hypotenuse $AC = 10 \, cm$.According to the Pythagorean theorem: $AC^2 = AB^2 + BC^2$.Substituting the values: $10^2 = AB^2 + 8^2$.$100 = AB^2 + 64$.$AB^2 = 100 - 64 = 36$.$AB = \sqrt{36} = 6 \, cm$.The area of a right triangle is given by the formula: $	ext{Area} = \frac{1}{2} 	imes 	ext{base} 	imes 	ext{height}$.$	ext{Area} = \frac{1}{2} 	imes 8 	imes 6 = 24 \, cm^2$.

The base of a right triangle is $8 \, cm$ and its hypotenuse is $10 \, cm$. Its area will be (in $cm^2$):

Similar Questions

$A$ design is made on a rectangular tile of dimensions $50\, cm \times 70\, cm$ as shown in the figure. The design shows $8$ triangles,each with sides $26\, cm, 17\, cm$,and $25\, cm$. Find the total area of the design and the remaining area of the tile.

Find the area of the trapezium $PQRS$ given in the figure.

Find the cost of laying grass in a triangular field of sides $50 \, m$,$65 \, m$,and $65 \, m$ at the rate of $Rs \, 7$ per $m^2$ (in $Rs$).

According to Heron's formula,the area of a triangle $=$ ...........

An isosceles triangle has a perimeter of $84 \, cm$ and each of the equal sides is $30 \, cm$. Find the area of the triangle.

Vedclass Test Series

Exam Paper Generator

Online Exam Module