The basic magnetization curve for a ferromagnetic material is shown in the figure. Then,the value of relative permeability is highest for the point

The relation between $\mu$ and $H$ for a specimen of iron is $\mu = [\frac{0.4}{H} + 12 \times 10^{-4}] \ H m^{-1}$. The value of $H$ which produces a flux density of $1 \ T$ will be ($\mu =$ magnetic permeability,$H =$ magnetic intensity).

The correct relation between total magnetic field $(B)$,magnetic intensity $(H)$,permeability of free space $(\mu_0)$ and susceptibility $(\chi)$ is

$A$ magnetizing field of $5000 \ A/m$ produces a magnetic flux of $4 \times 10^{-5} \ Wb$ in an iron rod of cross-sectional area $0.4 \ cm^2$. The permeability of the rod in $Wb/(A \cdot m)$ is:

The magnetic susceptibility of a material is $7.54 \times 10^{-3}$. The nature and relative permeability of the substance are:

$A$ substance has a mass of $0.075 \, kg$ and a density of $7500 \, kg/m^3$. If its magnetic dipole moment is $8 \times 10^{-7} \, A \cdot m^2$,what is its magnetization in $A/m$?