The binding energy per nucleon of ^{16}O is 7 | vedclass

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(C) The nuclear reaction for removing a neutron from $^{17}O$ is given by: $^{17}O 	o ^{16}O + _{0}^{1}n$.The total binding energy of a nucleus is ca

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$4.23$

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(C) The nuclear reaction for removing a neutron from $^{17}O$ is given by: $^{17}O 	o ^{16}O + _{0}^{1}n$.The total binding energy of a nucleus is calculated as: $BE = (	ext{number of nucleons}) 	imes (	ext{binding energy per nucleon})$.Total binding energy of $^{17}O = 17 	imes 7.75 \, MeV = 131.75 \, MeV$.Total binding energy of $^{16}O = 16 	imes 7.97 \, MeV = 127.52 \, MeV$.The energy required to remove the neutron is the difference in the total binding energies of the two nuclei:Energy required $= BE(^{17}O) - BE(^{16}O)$.Energy required $= 131.75 \, MeV - 127.52 \, MeV = 4.23 \, MeV$.

List $I$	List $II$
$(A)$ Fleming's left hand rule	$(i)$ Direction of induced current
$(B)$ Right hand thumb rule	(ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law	(iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule	(iv) Direction of magnetic lines due to current

The binding energy per nucleon of $^{16}O$ is $7.97 \, MeV$ and that of $^{17}O$ is $7.75 \, MeV$. The energy (in $MeV$) required to remove a neutron from $^{17}O$ is:

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