(C) In the compound $N \equiv C - CH = CH_2$,the carbon atom $(1)$ is bonded to nitrogen by a triple bond,so it is $sp$ hybridised.The carbon atom $(2

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(C) In the compound $N \equiv C - CH = CH_2$,the carbon atom $(1)$ is bonded to nitrogen by a triple bond,so it is $sp$ hybridised.The carbon atom $(2)$ is bonded to carbon $(1)$ by a single bond and to the other carbon by a double bond,so it is $sp^2$ hybridised.Therefore,the hybridisation of carbon $(1)$ and carbon $(2)$ is $sp$ and $sp^2$ respectively.

Class 11 Chemistry 8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds Bonding and hybridisation in organic compounds

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The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = CH_2$ involves the hybridised carbon as

IIT 1987 All IIT

A
$sp^2$ and $sp^2$
B
$sp^3$ and $sp$
C
$sp$ and $sp^2$
D
$sp$ and $sp$

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8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds

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Bonding and hybridisation in organic compounds

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Number of $sp$ hybridised carbon atoms in the given compound is:
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The hybridisation of each carbon in the following compound respectively is:
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The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = CH_2$ involves the hybridised carbon as

Similar Questions

The compound $1, 2-$butadiene has

The hybridisations of carbon-$2$ in $P$ and $Q$ are respectively:

The hybridization of carbon atoms in buta-$1,2$-diene is of the type........

Number of $sp$ hybridised carbon atoms in the given compound is:$CH_2 = CH - C \equiv C - CH_2 - CN$

The hybridisation of each carbon in the following compound respectively is:$CH_3-C(=O)-CH_2-CN$

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Number of $sp$ hybridised carbon atoms in the given compound is:
$CH_2 = CH - C \equiv C - CH_2 - CN$

The hybridisation of each carbon in the following compound respectively is:
$CH_3-C(=O)-CH_2-CN$