The bond dissociation energy of $B-F$ in $BF_3$ is $646 \ kJ \ mol^{-1}$ whereas that of $C-F$ in $CF_4$ is $515 \ kJ \ mol^{-1}.$ The correct reason for higher $B-F$ bond dissociation energy as compared to that of $C-F$ is

  • A
    stronger $\sigma$ bond between $B$ and $F$ in $BF_3$ as compared to that between $C$ and $F$ in $CF_4.$
  • B
    significant $p\pi - p\pi$ interaction between $B$ and $F$ in $BF_3$ whereas there is no possibility of such interaction between $C$ and $F$ in $CF_4.$
  • C
    lower degree of $p\pi - p\pi$ interaction between $B$ and $F$ in $BF_3$ than that between $C$ and $F$ in $CF_4.$
  • D
    smaller size of $B$ atom as compared to that of $C$ atom.

Explore More

Similar Questions

Covalent compounds are soluble in which of the following?

Which plot best represents the potential energy $(E)$ of two hydrogen atoms as they approach one another to form a hydrogen molecule?

Which one of the following compounds is hypervalent?

Which of the following has the least covalent $P-H$ bond?

$A$ covalent bond between two atoms is formed by which of the following?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo