The bond length of HCl molecule is 1.275 tex | vedclass

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(D) Given: Observed dipole moment $= 1.03 \ 	ext{D}$.Bond length of $HCl$ molecule,$d = 1.275 \ 	ext{Å} = 1.275 	imes 10^{-8} \ 	ext{cm}$.Charge o

Vedclass · Accepted Answer

$16.83$

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(D) Given: Observed dipole moment $= 1.03 \ 	ext{D}$.Bond length of $HCl$ molecule,$d = 1.275 \ 	ext{Å} = 1.275 	imes 10^{-8} \ 	ext{cm}$.Charge of electron,$e = 4.8 	imes 10^{-10} \ 	ext{esu}$.Theoretical dipole moment $= e 	imes d = (4.8 	imes 10^{-10} \ 	ext{esu}) 	imes (1.275 	imes 10^{-8} \ 	ext{cm}) = 6.12 	imes 10^{-18} \ 	ext{esu} \cdot 	ext{cm} = 6.12 \ 	ext{D}$.Percentage ionic character $= (	ext{Observed dipole moment} / 	ext{Theoretical dipole moment}) 	imes 100$.Percentage ionic character $= (1.03 / 6.12) 	imes 100 = 16.83 \%$.

The bond length of $HCl$ molecule is $1.275 \ \text{Å}$ and its dipole moment is $1.03 \ \text{D}$. The ionic character of the molecule (in percent) (charge of the electron $= 4.8 \times 10^{-10} \ \text{esu}$) is

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