The bond order and magnetic behaviour of $O_{2}^{-}$ ion are,respectively:
- A$1.5$ and paramagnetic
- B$1.5$ and diamagnetic
- C$2$ and diamagnetic
- D$1$ and paramagnetic
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Similar Questions
What is bond order? Explain with examples.
Medium
View SolutionMatch List-$I$ with List-$II$ and select the correct option:
List-$I$ (Molecule / ion) List-$II$ (Bond order) $1$. $NO$ $i$. $1.5$ $2$. $CO$ $ii$. $2.0$ $3$. $O_2^{-}$ $iii$. $2.5$ $4$. $O_2$ $iv$. $3.0$
| List-$I$ (Molecule / ion) | List-$II$ (Bond order) |
|---|---|
| $1$. $NO$ | $i$. $1.5$ |
| $2$. $CO$ | $ii$. $2.0$ |
| $3$. $O_2^{-}$ | $iii$. $2.5$ |
| $4$. $O_2$ | $iv$. $3.0$ |
MediumKCET 2025
View SolutionThe number of paramagnetic species among the following is $......$
$B_{2}, Li_{2}, C_{2}, C_{2}^{-}, O_{2}^{2-}, O_{2}^{+},$ and $He_{2}^{+}$
$B_{2}, Li_{2}, C_{2}, C_{2}^{-}, O_{2}^{2-}, O_{2}^{+},$ and $He_{2}^{+}$
Among $H_2, He_2^{+}, Li_2, Be_2, B_2, C_2, N_2, O_2^{-}$,and $F_2$,the number of diamagnetic species is (Atomic numbers: $H=1, He=2, Li=3, Be=4, B=5, C=6, N=7, O=8, F=9$)
MediumIIT 2017
View SolutionIn the following,the correct bond order sequence is:
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