The bottom of a cylindrical vessel has a hole of area $A$. If water is filled up to a height $h$,it flows out in $t$ seconds. If water is filled to a height $4h$,it will flow out in time:

$A$ cylindrical vessel of $40 \text{ cm}$ radius is completely filled with water and its capacity is $528 \text{ dm}^3$. The vessel is placed on a solid block of exactly the same height as the vessel. If a small hole is made at $70 \text{ cm}$ below the top of the water level, then the horizontal range of water falling on the ground in the beginning is . . . . . . $\text{cm}$.

$A$ tank is filled with water up to a height of $1 \, m$. $A$ hole is made at a distance of $20 \, cm$ from the top. Find the horizontal distance from the base of the tank where the water strikes the ground in $cm$.

The figure shows two holes in a wide tank containing a liquid column. The water streams coming out of these holes strike the ground at the same point. The height of the liquid column in the tank is $....\ cm$.

$A$ cylindrical vessel is filled with a liquid up to height $H$. $A$ small hole is made in the vessel at a distance $y$ below the liquid surface as shown in the figure. The liquid emerging from the hole strikes the ground at a distance $x$.

$A$ tank with a small hole at the bottom has been filled with water and kerosene (specific gravity $0.8$). The height of water is $3\,m$ and that of kerosene $2\,m$. When the hole is opened,the velocity of fluid coming out from it is nearly ........ $ms^{-1}$. (Take $g = 10\,ms^{-2}$ and density of water $= 10^3\,kg\,m^{-3}$)