The bowling average of a cricketer was 12.4. | vedclass

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Question

(C) Let the number of wickets taken by the cricketer before the last match be $x$.The total runs conceded before the last match $= 12.4x$.In the last

Vedclass · Accepted Answer

$175$

Vedclass · Answer

(C) Let the number of wickets taken by the cricketer before the last match be $x$.The total runs conceded before the last match $= 12.4x$.In the last match,he took $5$ wickets for $26$ runs.New total wickets $= x + 5$.New total runs $= 12.4x + 26$.The new bowling average is $12.4 - 0.2 = 12.2$.According to the problem:$\frac{12.4x + 26}{x + 5} = 12.2$$12.4x + 26 = 12.2(x + 5)$$12.4x + 26 = 12.2x + 61$$12.4x - 12.2x = 61 - 26$$0.2x = 35$$x = \frac{35}{0.2} = 175$.Therefore,the number of wickets taken before the last match was $175$.

The bowling average of a cricketer was $12.4$. He improves his bowling average by $0.2$ points when he takes $5$ wickets for $26$ runs in his last match. The number of wickets taken by him before the last match was?

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