(C) The molecular orbital $(MO)$ configuration of the superoxide ion,$O_{2}^{-} (17 \ e^{-})$,is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The molecular orbital $(MO)$ configuration of the superoxide ion,$O_{2}^{-} (17 \ e^{-})$,is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^1$. Bond order is calculated as: $\text{Bond order} = \frac{1}{2} (N_b - N_a) = \frac{1}{2} (10 - 7) = \frac{3}{2} = 1.5$.