The calculated magnetic moment (in Bohr magne | vedclass

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(A) The atomic number of $Cu$ is $29$. The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$.For $Cu^{2+}$ ion,two electrons are removed (one fr

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$1.73$

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(A) The atomic number of $Cu$ is $29$. The electronic configuration of $Cu$ is $[Ar] 3d^{10} 4s^1$.For $Cu^{2+}$ ion,two electrons are removed (one from $4s$ and one from $3d$),resulting in the configuration $[Ar] 3d^9$.In the $3d^9$ configuration,there is $1$ unpaired electron $(n = 1)$.The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} 	ext{ BM}$.$\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 	ext{ BM}$.

List-$I$ Species	List-$II$ Electronic distribution
$A$. $Cr^{2+}$	$I$. $3d^8$
$B$. $Mn^{+}$	$II$. $3d^3 4s^1$
$C$. $Ni^{2+}$	$III$. $3d^4$
$D$. $V^{+}$	$IV$. $3d^5 4s^1$

The calculated magnetic moment (in Bohr magnetons) of $Cu^{2+}$ ion is:

Similar Questions

Match List-$I$ with List-$II$

List-$I$ Species List-$II$ Electronic distribution

$A$. $Cr^{2+}$ $I$. $3d^8$

$B$. $Mn^{+}$ $II$. $3d^3 4s^1$

$C$. $Ni^{2+}$ $III$. $3d^4$

$D$. $V^{+}$ $IV$. $3d^5 4s^1$

Choose the correct answer from the options given below:

Which of the following factors may be regarded as the main cause of lanthanide contraction?

The number of valence electrons present in the metal among $Cr$,$Co$,$Fe$,and $Ni$ which has the lowest enthalpy of atomisation is

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Out of all the known elements,the number of transition elements is:

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