The calculated spin-only magnetic moment of C | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.For $Cr^{2+}$ ion,two electrons are removed,resulting in the configuration $[Ar] 3d^4$.Th

Vedclass · Accepted Answer

$4.90$

Vedclass · Answer

(C) The electronic configuration of $Cr$ is $[Ar] 3d^5 4s^1$.For $Cr^{2+}$ ion,two electrons are removed,resulting in the configuration $[Ar] 3d^4$.This means there are $n = 4$ unpaired electrons.The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$Substituting $n = 4$:$\mu = \sqrt{4(4+2)} \ B.M. = \sqrt{4 	imes 6} \ B.M. = \sqrt{24} \ B.M. \approx 4.90 \ B.M.$

The calculated spin-only magnetic moment of $Cr^{2+}$ ion is......$B.M.$

Similar Questions

Which of the following has a colored aqueous solution?

The number of unpaired electrons in the $Cr^{3+}$ ion is . . . . .

The melting point of $Zn$ is lower compared to those of the other elements of the $3d$ series because $-$

In which of the following cases,the stability of two oxidation states is correctly represented?

Ferrous ion changes to $X$ ion upon reacting with acidified hydrogen peroxide. The number of $d$-electrons present in $X$ and its magnetic moment (in $BM$) are,respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module