The calculated spin-only magnetic moment of $Cr^{2+}$ ion is: (in $text{ BM}$)

The electronic structure $(n - 1)d^{1 - 10}ns^{0 - 2}$ is characteristic of

Match the following:

List-$I$ (Transition metal,$M$)	List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$)
$A$. $Ni$	$I$. $-1.18$
$B$. $Mn$	$II$. $-0.91$
$C$. $Fe$	$III$. $-0.25$
$D$. $Cr$	$IV$. $-0.44$

The correct answer is

The elements belonging to the first transition series have atomic numbers from

Identify the correct decreasing order of densities of $d-$block elements.

$A$ transition metal $M$ among $Sc, Ti, V, Cr, Mn$ and $Fe$ has the highest second ionisation enthalpy. The spin only magnetic moment value of $M^{+}$ ion is $. . . . . . . BM$ (Near integer)
(Given atomic number $Sc: 21, Ti: 22, V: 23, Cr: 24, Mn: 25, Fe: 26$)