(A) $1$. The two capacitors of $1.5 \,\mu F$ are connected in parallel. Their equivalent capacitance is $C_p = 1.5 \,\mu F + 1.5 \,\mu F = 3 \,\mu F$.

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(A) $1$. The two capacitors of $1.5 \,\mu F$ are connected in parallel. Their equivalent capacitance is $C_p = 1.5 \,\mu F + 1.5 \,\mu F = 3 \,\mu F$.$2$. Now,the circuit consists of three capacitors of $3 \,\mu F$ each,connected in series.$3$. The equivalent capacitance $C_{AB}$ is given by $\frac{1}{C_{AB}} = \frac{1}{3} + \frac{1}{3} + \frac{1}{3} = \frac{3}{3} = 1$.$4$. Therefore,$C_{AB} = 1 \,\mu F$.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

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The capacitance between the points $A$ and $B$ in the given circuit will be.......$\mu F$.

A
$1$
B
$2$
C
$3$
D
$4$

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

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The equivalent capacitance between $A$ and $B$ is......$\mu F$.

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The capacitance between the points $A$ and $B$ in the given circuit will be.......$\mu F$.

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What is a series connection of capacitors? Obtain the formula for the effective capacitance in the series combination of two different capacitors.

The figure shows a network of five capacitors connected to a supply voltage '$V$'. The equivalent capacitance and the energy stored in the network are respectively:

In the given diagram, the potential difference $(PD)$ between $A$ and $B$ is $60 \, V$. The potential difference across the $6 \, \mu F$ capacitor is: (in $V$)

If the equivalent capacitance between $A$ and $B$ of the combination of capacitors shown in the figure is $3 C$,then the capacitor $C^{\prime}$ is equal to: (in $C$)

The equivalent capacitance between $A$ and $B$ is......$\mu F$.

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