The capacitance of an air capacitor is $15\,\mu F$ and the separation between the parallel plates is $6\,mm$. $A$ copper plate of $3\,mm$ thickness is introduced symmetrically between the plates. The capacitance now becomes.........$\mu F$.

  • A
    $5$
  • B
    $7.5$
  • C
    $22.5$
  • D
    $30$

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