(C) When capacitors are connected in series,the equivalent capacitance $C_{eq}$ is given by the formula: $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{

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(C) When capacitors are connected in series,the equivalent capacitance $C_{eq}$ is given by the formula: $\frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2}$.Substituting the given values $C_1 = 4\,\mu F$ and $C_2 = 6\,\mu F$:$C_{eq} = \frac{C_1 C_2}{C_1 + C_2} = \frac{4 \times 6}{4 + 6} = \frac{24}{10} = 2.4\,\mu F$.The charge $Q$ on each capacitor in a series combination is the same and is given by $Q = C_{eq} \times V$.Given $V = 500\;V$,we have:$Q = 2.4\,\mu F \times 500\;V = 1200\;\mu C$.

Class 12 Physics Electric Potential and Capacitance Equivalent Capacitance of Capacitor connected in Series and Parallel

Medium

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\;V$ is applied to the outer plates of the two-capacitor system. The charge on each capacitor is numerically:

A
$6000\;C$
B
$1200\;C$
C
$1200\;\mu C$
D
$6000\;\mu C$

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Electric Potential and Capacitance

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Equivalent Capacitance of Capacitor connected in Series and Parallel

In the circuit shown in the figure,$C = 6\,\mu F$. The charge stored in the capacitor of capacity $C$ is......$\mu C$.

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Two capacitors $A$ and $B$ are connected in series as shown in the figure. When the switch $S$ is closed and both capacitors are fully charged,then:

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As shown in the figure, a potential of $+1200\, V$ is applied at point $A$, and point $B$ is kept at zero potential. Then the electric potential at point $P$ is.....$V$

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Find the equivalent capacitance between points $A$ and $B$ in the given figure. (in $\mu F$)

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Two condensers of capacities $C$ and $2C$ are connected in parallel and then in series with a $3^{\text{rd}}$ condenser of capacity $3C$. The combination is charged to $V$ volts. The charge on the condenser of capacity $C$ is:

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Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\;V$ is applied to the outer plates of the two-capacitor system. The charge on each capacitor is numerically:

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In the circuit shown in the figure,$C = 6\,\mu F$. The charge stored in the capacitor of capacity $C$ is......$\mu C$.

Two capacitors $A$ and $B$ are connected in series as shown in the figure. When the switch $S$ is closed and both capacitors are fully charged,then:

As shown in the figure, a potential of $+1200\, V$ is applied at point $A$, and point $B$ is kept at zero potential. Then the electric potential at point $P$ is.....$V$

Find the equivalent capacitance between points $A$ and $B$ in the given figure. (in $\mu F$)

Two condensers of capacities $C$ and $2C$ are connected in parallel and then in series with a $3^{\text{rd}}$ condenser of capacity $3C$. The combination is charged to $V$ volts. The charge on the condenser of capacity $C$ is:

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