Two capacitors of capacitance 4,mu F and 6,mu | vedclass

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(B) When capacitors are connected in series,the charge $Q$ on each capacitor is the same.For capacitors in series,the potential difference $V_1$ acros

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(B) When capacitors are connected in series,the charge $Q$ on each capacitor is the same.For capacitors in series,the potential difference $V_1$ across a capacitor $C_1$ is given by the formula $V_1 = V 	imes \left( \frac{C_2}{C_1 + C_2} ight)$,where $V$ is the total potential difference.Given: $C_1 = 4\,\mu F$,$C_2 = 6\,\mu F$,and $V = 500\,V$.Substituting the values:$V_1 = 500 	imes \left( \frac{6}{4 + 6} ight)$$V_1 = 500 	imes \left( \frac{6}{10} ight)$$V_1 = 500 	imes 0.6 = 300\,V$.Therefore,the potential difference across the $4\,\mu F$ capacitor is $300\,V$.

Two capacitors of capacitance $4\,\mu F$ and $6\,\mu F$ are connected in series. $A$ potential difference of $500\,V$ is applied to the outer plates of the two-capacitor system. The potential difference across the plates of the $4\,\mu F$ capacitor is ......... $V$.

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