The cell constant of a given cell is $0.47 \, cm^{-1}$. The resistance of a solution placed in this cell is measured to be $31.6 \, \Omega$. The conductivity of the solution (in $S \, cm^{-1}$ where $S$ has usual meaning) is
- A$0.15$
- B$1.5$
- C$0.015$
- D$150$
Explore More
Similar Questions
The dissociation constant of $n$-butyric acid is $1.6 \times 10^{-5}$ and the molar conductivity at infinite dilution is $380 \times 10^{-4} \ S \ m^2 \ mol^{-1}$. The specific conductance of the $0.01 \ M$ acid solution is
Medium
View Solution$A$ conductivity cell has two electrodes $18 \ mm$ apart and having cross-sectional area $2.0 \ cm^2$. What is the value of the cell constant (in $cm^{-1}$)?
Metallic conductors and semiconductors are heated separately. What are the changes with respect to conductivity?
The ionic conductances of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. The equivalent conductance of $BaCl_2$ at infinite dilution is ..... (in $.5$)
Medium
View SolutionIf $l = \text{length}$,$R = \text{Resistance}$,and $A = \text{Area of cross-section}$,then which of the following relations is correct?
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo