The chances of throwing a total of 3 or 5 or | vedclass

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Question

(C) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the favorable outcomes for getting a sum of $3

Vedclass · Accepted Answer

$\frac{2}{9}$

Vedclass · Answer

(C) When two dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.We need to find the favorable outcomes for getting a sum of $3$,$5$,or $11$:- For a sum of $3$: The possible outcomes are $(1, 2)$ and $(2, 1)$. (Total $2$ cases)- For a sum of $5$: The possible outcomes are $(1, 4), (2, 3), (3, 2),$ and $(4, 1)$. (Total $4$ cases)- For a sum of $11$: The possible outcomes are $(5, 6)$ and $(6, 5)$. (Total $2$ cases)Total favorable outcomes $= 2 + 4 + 2 = 8$.The required probability is $\frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} = \frac{8}{36} = \frac{2}{9}$.

The chances of throwing a total of $3$ or $5$ or $11$ with two dice is

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