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(C) From the circuit diagram:$X = P + Q$$Y = 	ext{NOT}(	ext{NAND}(R, S)) = 	ext{NOT}(	ext{NOT}(R \cdot S)) = R \cdot S$$Z = 	ext{NOR}(X, Y) = 	e

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$0, 1, 0$

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(C) From the circuit diagram:$X = P + Q$$Y = 	ext{NOT}(	ext{NAND}(R, S)) = 	ext{NOT}(	ext{NOT}(R \cdot S)) = R \cdot S$$Z = 	ext{NOR}(X, Y) = 	ext{NOT}(X + Y)$Given inputs: $P = 0, Q = 0, R = 1, S = 1$.Calculating $X$:$X = 0 + 0 = 0$Calculating $Y$:$Y = 1 \cdot 1 = 1$Calculating $Z$:$Z = 	ext{NOT}(X + Y) = 	ext{NOT}(0 + 1) = 	ext{NOT}(1) = 0$Thus,the states of outputs $X, Y, Z$ are $0, 1, 0$ respectively.

The circuit diagram shows a combination of logic gates. When inputs $P$ and $Q$ change to state $0$ with inputs $R$ and $S$ still at state $1$,the states of outputs $X$,$Y$ and $Z$ change to:

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