The circuit shown consists of a switch S,a ba | vedclass

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(D) When the switch $S$ is closed at time $t = 0$,the inductor $L$ opposes any change in the current flowing through it.According to Lenz's law,the in

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(D) When the switch $S$ is closed at time $t = 0$,the inductor $L$ opposes any change in the current flowing through it.According to Lenz's law,the induced emf in the inductor is given by $\varepsilon = -L(di/dt)$.At the instant $t = 0$,the current in the circuit is zero,and the inductor acts as an open circuit (infinite resistance) to prevent the sudden change in current.Therefore,the current in the circuit at the instant the switch is closed is $i = 0$.

The circuit shown consists of a switch $S$,a battery $B$ of emf $E$,a resistance $R$,and an inductor $L$. What is the current in the circuit at the instant the switch $S$ is closed?

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