The circuit shown in the figure contains two ideal diodes $D_1$ and $D_2$. If a cell of emf $3 \text{ V}$ and negligible internal resistance is connected as shown,then the current through the $70 \Omega$ resistance (in ampere) is:

If a diode having infinite reverse bias resistance is connected in a circuit as shown in the figure,then $I_1$ and $I_2$ are respectively:

$A$ junction diode has a resistance of $25 \Omega$ when forward biased and $2500 \Omega$ when reverse biased. The current in the diode, for the arrangement shown, will be

With forward bias mode,the $p-n$ junction diode

$A$ diode having a potential difference of $0.5\, V$ across its junction,which does not depend on the current,is connected in series with a resistance of $20\, \Omega$ across a source. If $0.1\, A$ passes through the resistance,then what is the voltage of the source (in $, V$)?

In a semiconductor diode,the forward voltage is increased from $0.5 \ V$ to $0.7 \ V$. As a result,the forward current changes by $1 \ mA$. The forward resistance of the diode is ....... $\Omega$.