The coefficient of $x^r$ in the expansion of $\frac{1}{\sqrt[3]{(1-2 x)^2}}$ is

  • A
    $\frac{2 \cdot 5 \cdot 8 \ldots(3 r-1)}{r !}(-1)^r\left(\frac{2}{3}\right)^r$
  • B
    $\frac{2 \cdot 5 \cdot 8 \ldots(3 r-1)}{r !}(-1)^r\left(\frac{3}{2}\right)^r$
  • C
    $\frac{2 \cdot 5 \cdot 8 \ldots(3 r-1)}{r !}\left(\frac{2}{3}\right)^r$
  • D
    $\frac{2 \cdot 5 \cdot 8 \ldots(3 r-1)}{r !}\left(\frac{3}{2}\right)^{r}$

Explore More

Similar Questions

If $|x| < \frac{1}{2}$,then the coefficient of $x^r$ in the expansion of $\frac{1+2x}{(1-2x)^2}$ is

If the set of all values of $x$ for which the expansion of $(7-5 x)^{-\frac{2}{3}}$ is valid is equal to $(-a, a)$,then $5 a+7$ is equal to

If $|x| > 1$,then $(1 + x)^{-2} = $

Difficult
View Solution

For $x=\frac{5}{7}$,if $t_k$ is the first negative term in the expansion of $(1+x)^{7/5}$,then $t_1+t_2+\ldots+t_k=$

For $x>0$,if $p^{\text{th}}$ term is the first negative term in the expansion of $(1+\frac{3x}{5})^{22/3}$ and in the expansion of $(1-\frac{3x}{5})^{22/3}$ from $r^{\text{th}}$ term onwards all the terms are positive,then the number of terms in the expansion of $(px+\frac{r}{x})^{pr}$ is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo