The coefficient of apparent expansion of a li | vedclass

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(D) The real coefficient of expansion of a liquid is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{app}} + \gamma_{	ext{vessel}}$.Here

Vedclass · Accepted Answer

$\frac{\gamma_1 - \gamma_2}{3} + \alpha$

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(D) The real coefficient of expansion of a liquid is given by the relation: $\gamma_{	ext{real}} = \gamma_{	ext{app}} + \gamma_{	ext{vessel}}$.Here,$\gamma_{	ext{vessel}} = 3\alpha_{	ext{vessel}}$,where $\alpha_{	ext{vessel}}$ is the coefficient of linear expansion.For vessel $A$: $\gamma_{	ext{real}} = \gamma_1 + 3\alpha$.For vessel $B$: $\gamma_{	ext{real}} = \gamma_2 + 3\alpha_B$,where $\alpha_B$ is the coefficient of linear expansion of vessel $B$.Since the liquid is the same,$\gamma_{	ext{real}}$ is constant. Equating the two expressions:$\gamma_1 + 3\alpha = \gamma_2 + 3\alpha_B$$3\alpha_B = \gamma_1 - \gamma_2 + 3\alpha$$\alpha_B = \frac{\gamma_1 - \gamma_2}{3} + \alpha$.

The coefficient of apparent expansion of a liquid when determined using two different vessels $A$ and $B$ are $\gamma_1$ and $\gamma_2$ respectively. If the coefficient of linear expansion of the vessel $A$ is $\alpha$,then find the coefficient of linear expansion of vessel $B$.

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