(D) For the system to be in equilibrium,the tension $T$ in the string must balance the weight of block $B$ and the limiting friction force on block $A

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(D) For the system to be in equilibrium,the tension $T$ in the string must balance the weight of block $B$ and the limiting friction force on block $A$.For block $B$: $T = m_B g$For block $A$: $T = f_s = \mu_s N = \mu_s m_A g$Equating the two expressions for $T$: $m_B g = \mu_s m_A g$$m_B = \mu_s m_A$Given $\mu_s = 0.2$ and $m_A = 2\, kg$:$m_B = 0.2 \times 2 = 0.4\, kg$Therefore,the maximum mass of block $B$ is $0.4\, kg$.

Class 11 Physics Newton's Laws of Motion and Friction Static and Limiting Friction and Minimum Force Required to Move

Medium

The coefficient of static friction,$\mu_s$,between block $A$ of mass $2\, kg$ and the table as shown in the figure is $0.2$. Find the maximum mass value of block $B$ in $kg$ so that the two blocks do not move. The string and the pulley are assumed to be smooth and massless. $(g = 10\, m/s^2)$

AIPMT 2004 All AIPMT

A
$2.0$
B
$4.0$
C
$0.2$
D
$0.4$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Newton's Laws of Motion and Friction

Subtopic

Static and Limiting Friction and Minimum Force Required to Move

Previous Year

AIPMT 2004 Paper All AIPMT years →

$A$ block of mass $2\,kg$ is at rest on a floor. The coefficient of static friction between the block and the floor is $0.54$. $A$ horizontal force of $2.8\,N$ is applied to the block. What will be the frictional force between the block and the floor (in $.8$)? $(g = 10\,m/s^2)$

Medium

View Solution

$A$ block of $1\, kg$ is stopped against a wall by applying a force $F$ perpendicular to the wall. If $\mu = 0.2$,then the minimum value of $F$ will be ....... $N$.

Easy

View Solution

Is it possible to jump off a perfectly smooth surface? Why?

Medium

View Solution

The maximum force of friction is called:

Easy

View Solution

$A$ block of mass $m$ is pressed against a vertical surface by a spring of unstretched length $l$. The spring is compressed by a distance $d$ as shown in the figure. If the coefficient of friction between the block and the surface is $\mu$,choose the correct statement.

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The coefficient of static friction,$\mu_s$,between block $A$ of mass $2\, kg$ and the table as shown in the figure is $0.2$. Find the maximum mass value of block $B$ in $kg$ so that the two blocks do not move. The string and the pulley are assumed to be smooth and massless. $(g = 10\, m/s^2)$

Similar Questions

$A$ block of mass $2\,kg$ is at rest on a floor. The coefficient of static friction between the block and the floor is $0.54$. $A$ horizontal force of $2.8\,N$ is applied to the block. What will be the frictional force between the block and the floor (in $.8$)? $(g = 10\,m/s^2)$

$A$ block of $1\, kg$ is stopped against a wall by applying a force $F$ perpendicular to the wall. If $\mu = 0.2$,then the minimum value of $F$ will be ....... $N$.

Is it possible to jump off a perfectly smooth surface? Why?

The maximum force of friction is called:

$A$ block of mass $m$ is pressed against a vertical surface by a spring of unstretched length $l$. The spring is compressed by a distance $d$ as shown in the figure. If the coefficient of friction between the block and the surface is $\mu$,choose the correct statement.

Vedclass Test Series

Exam Paper Generator

Online Exam Module