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(B) In the photoelectric effect,when a light source is incident on the emitter plate,electrons are ejected with some initial kinetic energy.Since the

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The kinetic energy of the electrons will increase.

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(B) In the photoelectric effect,when a light source is incident on the emitter plate,electrons are ejected with some initial kinetic energy.Since the collector plate is above the emitter plate and the electric field $\vec{E}$ is directed vertically downward,the force $\vec{F} = q\vec{E}$ on the electrons (where $q = -e$) will be directed vertically upward.Because the force on the electrons is in the same direction as their motion towards the collector plate,the electric field does positive work on the electrons.As a result,the kinetic energy $(K.E.)$ of the photoelectrons increases as they move towards the collector plate.Since the kinetic energy of the electrons reaching the collector plate increases,a larger retarding potential is required to stop them,meaning the stopping potential will increase.The photocurrent remains unchanged as long as the saturation condition is met,and the threshold wavelength is a property of the material,which remains unaffected by the external electric field.Therefore,the correct statement is that the kinetic energy of the electrons will increase.

The collector plate in an experiment on the photoelectric effect is kept vertically above the emitter plate. $A$ light source is turned on and a saturation photocurrent is recorded. An electric field is then switched on which has a vertically downward direction.

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