The combination of capacitors with C_1 = 3,mu | vedclass

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(B) From the circuit diagram,$C_2$ and $C_3$ are connected in parallel,and this parallel combination is in series with $C_1$.$1$. For charge distribut

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$II$ only

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(B) From the circuit diagram,$C_2$ and $C_3$ are connected in parallel,and this parallel combination is in series with $C_1$.$1$. For charge distribution: The total charge $Q$ flowing from the battery passes through $C_1$. This charge then splits into $Q_2$ and $Q_3$ across $C_2$ and $C_3$ respectively. Thus,$Q = Q_2 + Q_3$. Statement $II$ is correct.$2$. For potential drop: Since $C_2$ and $C_3$ are in parallel,the potential drop across them is the same $(V_2 = V_3)$. However,the potential drop across $C_1$ $(V_1 = Q/C_1)$ is generally not equal to the potential drop across the parallel combination $(V_{23} = Q/(C_2+C_3))$. Thus,statement $III$ is incorrect.$3$. For energy stored: Energy stored in a capacitor is $U = Q^2 / (2C)$. Since $Q_1 = Q$,$U_1 = Q^2 / (2C_1)$. The energy in the parallel combination is $U_{23} = Q_2^2 / (2C_2) + Q_3^2 / (2C_3)$. These are not generally equal. Thus,statement $I$ is incorrect.Therefore,only statement $II$ is correct.

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