The correct order of melting points of hydrid | vedclass

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(A) The melting points of group $16$ hydrides $(H_{2}O, H_{2}S, H_{2}Se, H_{2}Te)$ depend on the intermolecular forces of attraction. $H_{2}O$ has the

Vedclass · Accepted Answer

$H_{2}S < H_{2}Se < H_{2}Te < H_{2}O$

Vedclass · Answer

(A) The melting points of group $16$ hydrides $(H_{2}O, H_{2}S, H_{2}Se, H_{2}Te)$ depend on the intermolecular forces of attraction. $H_{2}O$ has the highest melting point due to strong intermolecular hydrogen bonding. For the remaining hydrides $(H_{2}S, H_{2}Se, H_{2}Te)$,the melting point increases down the group due to an increase in molecular mass and the resulting increase in van der Waals forces. Therefore,the correct order is $H_{2}S < H_{2}Se < H_{2}Te < H_{2}O$.

The correct order of melting points of hydrides of group $16$ elements is $...$

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