The compound A in the following reaction is:A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The product formed from $D$ by the action of $Ba(OH)_2$ and $\Delta$ is mesityl oxide $(CH_3-C(CH_3)=CH-CO-CH_3)$,which is a self-aldol condensati

Vedclass · Accepted Answer

$C_6H_5-CH_2-CO-CH_3$

Vedclass · Answer

(A) The product formed from $D$ by the action of $Ba(OH)_2$ and $\Delta$ is mesityl oxide $(CH_3-C(CH_3)=CH-CO-CH_3)$,which is a self-aldol condensation product of acetone. Therefore,$D$ is acetone $(CH_3-CO-CH_3)$.Since ozonolysis of $B$ gives $C$ and $D$ (acetone),$B$ must contain the $(CH_3)_2C=$ group.When $A$ $(C_6H_5-CH_2-CO-CH_3)$ reacts with $CH_3MgBr$ followed by dehydration with $Conc. H_2SO_4$,it forms $B$ $(C_6H_5-CH=C(CH_3)_2)$.$C_6H_5-CH_2-CO-CH_3$ $\xrightarrow{CH_3MgBr} C_6H_5-CH_2-C(OH)(CH_3)_2$ $\xrightarrow{H^{+}, \Delta} C_6H_5-CH=C(CH_3)_2 (B)$.Ozonolysis of $B$: $C_6H_5-CH=C(CH_3)_2 \xrightarrow{O_3/Zn, H_2O} C_6H_5-CHO (C) + CH_3-CO-CH_3 (D)$.

The compound $A$ in the following reaction is:
$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$
$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$

Similar Questions

Arrange the following compounds in increasing order of their reactivity in nucleophilic addition reactions.
$(i)$ Ethanal,Propanal,Propanone,Butanone.
$(ii)$ Benzaldehyde,$p-$Tolualdehyde,$p-$Nitrobenzaldehyde,Acetophenone.
Hint: Consider steric effect and electronic effect.

Which of the following is not true about acetophenone?

The reaction $R-C(=O)-R + HCN \xrightarrow{\text{catalyst}} R-C(OH)(CN)-R$ is a nucleophilic addition reaction. Which of the following can be used as a catalyst in the above reaction?

The products $A$,$B$ and $C$ in the following reaction sequence are:

Arrange the following compounds in increasing order of their reactivity towards $HCN$:
$I$. Acetaldehyde
$II$. Acetone
$III$. Di-tert-butyl ketone
$IV$. Methyl-tert-butyl ketone

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The compound $A$ in the following reaction is:$A$ $\xrightarrow[(ii) Conc. H_2SO_4 / \Delta]{(i) CH_3MgBr / H_2O} B$ $\xrightarrow[(ii) Zn / H_2O]{(i) O_3} C + D$$D \xrightarrow[Ba(OH)_2, \Delta]{} CH_3-C(CH_3)=CH-CO-CH_3$