The compound B formed in the following sequen | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: $CH_3-CH_2-CH_2-OH$ reacts with $PCl_3$ to form $1$-chloropropane $(A)$ via nucleophilic substitution.$CH_3-CH_2-CH_2-OH + PCl_3 \righta

Vedclass · Accepted Answer

Propene

Vedclass · Answer

(B) Step $1$: $CH_3-CH_2-CH_2-OH$ reacts with $PCl_3$ to form $1$-chloropropane $(A)$ via nucleophilic substitution.$CH_3-CH_2-CH_2-OH + PCl_3 \rightarrow CH_3-CH_2-CH_2-Cl (A) + H_3PO_3$Step $2$: $1$-chloropropane $(A)$ reacts with alcoholic $KOH$ to undergo dehydrohalogenation (elimination reaction) to form propene $(B)$.$CH_3-CH_2-CH_2-Cl + Alco. KOH \rightarrow CH_3-CH=CH_2 (B) + KCl + H_2O$Therefore,the compound $B$ is propene.

The compound $B$ formed in the following sequence of reactions is:
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{PCl_3} A$ $\xrightarrow{Alco. KOH} B$

Similar Questions

Which reaction is known as Kharash reaction?

The addition of $HI$ to the double bond of propene yields isopropyl iodide and not $n$-propyl iodide because the addition proceeds through the formation of:

Choose the correct product of the following reaction:
$1$,$2$-dimethylcyclopent$-1-$ene $\xrightarrow[2. H_3O^+]{1. mCPBA}$ Product

Which reaction is not possible?

$CH_2=CHCl$ reacts with $HCl$ to form

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The compound $B$ formed in the following sequence of reactions is:$CH_3-CH_2-CH_2-OH$ $\xrightarrow{PCl_3} A$ $\xrightarrow{Alco. KOH} B$